The ball is projected from a height of 25m above the ground and is thrown with an initial velocity of 8.25 m/s? - m.s more condition_symptoms
a.how takes the ball in the air before touching the ground? b.How the construction of the strikes do not have the earth?
1 comment:
a) 25 m ^ 2 = 1/2at
25/4.9 = t ^ 2 = 5.1, SQ-RT = T = 2.2587 seconds
b) 8.25 x 2.2587 = 18.63 m
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